Electricity MCQ Practice: 100 Questions for Class X Physics with Solutions

SECTION A - QUESTIONS

LEVEL 1: SIMPLEST (Questions 1-15)

1. The SI unit of electric current is:

(A) Volt

(B) Ampere

(D) Coulomb

2. The SI unit of potential difference is:

(A) Ampere

(B) Volt

(D) Joule

3. The SI unit of resistance is:

(A) Volt

(B) Ampere

(D) Watt

4. Electric current is measured by:

(A) Voltmeter

(B) Ammeter

(D) Ohmmeter

5. Potential difference is measured by:

(A) Ammeter

(B) Voltmeter

(D) Ohmmeter

6. 1 Ampere = ?

(A) 1 Coulomb/second

(B) 1 Volt/second

(D) 1 Joule/second

7. 1 Volt = ?

(A) 1 Ampere/Coulomb

(B) 1 Joule/Coulomb

(D) 1 Ohm/Coulomb

8. According to Ohm's law, V = ?

(A) I/R

(B) IR

(D) I - R

9. The direction of conventional current is:

(A) Positive to negative

(B) Negative to positive

(D) Depends on material

10. Electric charge is measured in:

(A) Ampere

(B) Volt

(D) Ohm

11. The symbol for resistance is:

(A) I

(B) V

(D) P

12. The symbol for current is:

(A) I

(B) V

(D) C

13. Power is measured in:

(A) Joule

(B) Watt

(D) Ampere

14. Energy is measured in:

(A) Watt

(B) Joule

(D) Ohm

15. 1 kWh = ? Joules

(A) 3.6 × 103 J

(B) 3.6 × 106 J

(D) 3600 J

LEVEL 2: SIMPLE (Questions 16-30)

16. If 10 C charge flows in 5 seconds, the current is:

(A) 2 A

(B) 50 A

(D) 0.5 A

17. A current of 2 A flows for 10 seconds. The charge that flows is:

(A) 5 C

(B) 20 C

(D) 0.2 C

18. If V = 12 V and I = 3 A, then R = ?

(A) 36 Ω

(B) 4 Ω

(D) 15 Ω

19. If R = 5 Ω and I = 2 A, then V = ?

(A) 2.5 V

(B) 10 V

(D) 3 V

20. If V = 24 V and R = 8 Ω, then I = ?

(A) 192 A

(B) 3 A

(D) 32 A

21. Two resistors of 4 Ω and 6 Ω in series have total resistance:

(A) 2.4 Ω

(B) 10 Ω

(D) 24 Ω

22. Two resistors of 4 Ω and 6 Ω in parallel have total resistance:

(A) 10 Ω

(B) 2.4 Ω

(D) 1 Ω

23. Power P = VI. If V = 10 V and I = 2 A, then P = ?

(A) 5 W

(B) 20 W

(D) 8 W

24. If P = 100 W and V = 220 V, then I = ?

(A) 22000 A

(B) 0.45 A

(D) 320 A

25. Heat produced H = I2Rt. If I = 2 A, R = 5 Ω, t = 10 s, then H = ?

(A) 100 J

(B) 200 J

(D) 400 J

26. Three resistors each of 6 Ω are connected in series. Total resistance is:

(A) 2 Ω

(B) 6 Ω

(D) 12 Ω

27. Three resistors each of 9 Ω are connected in parallel. Total resistance is:

(A) 27 Ω

(B) 9 Ω

(D) 1 Ω

28. A device consumes 1 kW power for 2 hours. Energy consumed is:

(A) 2 kWh

(B) 0.5 kWh

(D) 1 kWh

29. Resistance depends on:

(A) Length only

(B) Area only

(D) All of the above

30. If length of wire is doubled, resistance becomes:

(A) Half

(B) Double

(D) Same

LEVEL 3: EASY (Questions 31-50)

31. If area of cross-section is doubled, resistance becomes:

(A) Double

(B) Half

(D) Same

32. Resistivity has units:

(A) Ω

(B) Ω⋅m

(D) m/Ω

33. Which has highest resistivity?

(A) Copper

(B) Silver

(D) Aluminum

34. An ammeter should have:

(A) High resistance

(B) Low resistance

(D) Infinite resistance

35. A voltmeter should have:

(A) Low resistance

(B) High resistance

(D) Same as circuit resistance

36. Ammeter is connected in:

(A) Series

(B) Parallel

(D) Neither way

37. Voltmeter is connected in:

(A) Series

(B) Parallel

(D) Neither way

38. In series combination, current is:

(A) Different in each resistor

(B) Same in each resistor

(D) Maximum in largest resistor

39. In parallel combination, voltage is:

(A) Different across each resistor

(B) Same across each resistor

(D) Maximum across largest resistor

40. Power consumed by 100 W bulb in 5 hours is:

(A) 500 Wh

(B) 0.5 kWh

(D) 100 kWh

41. Electric power P = V2/R. If V = 220 V and R = 100 Ω, then P = ?

(A) 484 W

(B) 2.2 W

(D) 48400 W

42. Current through a 60 W, 220 V bulb is:

(A) 0.27 A

(B) 3.67 A

(D) 13200 A

43. Resistance of 100 W, 220 V bulb is:

(A) 484 Ω

(B) 2.2 Ω

(D) 22000 Ω

44. Fuse wire is made of:

(A) Copper

(B) Silver

(D) Iron

45. Fuse is connected in:

(A) Series with live wire

(B) Parallel with live wire

(D) Parallel with neutral wire

46. Good conductors have:

(A) High resistivity

(B) Low resistivity

(D) Infinite resistivity

47. Good insulators have:

(A) Low resistivity

(B) High resistivity

(D) Negative resistivity

48. When resistors are in series, total resistance is:

(A) Less than smallest resistance

(B) Greater than largest resistance

(D) Zero

49. When resistors are in parallel, total resistance is:

(A) Greater than largest resistance

(B) Less than smallest resistance

(D) Infinite

50. Heating effect of current is used in:

(A) Electric heater

(B) Electric iron

(D) All of the above

LEVEL 4: MODERATE (Questions 51-70)

51. Two bulbs 40 W and 60 W are connected in series to 220 V supply. Which bulb glows brighter?

(A) 40 W bulb

(B) 60 W bulb

(D) Neither glows

52. Two bulbs 40 W and 60 W are connected in parallel to 220 V supply. Which bulb glows brighter?

(A) 40 W bulb

(B) 60 W bulb

(D) Neither glows

53. A wire of resistance 10 Ω is bent to form a circle. Resistance between two diametrically opposite points is:

(A) 2.5 Ω

(B) 5 Ω

(D) 20 Ω

54. If voltage across a resistor is halved, power becomes:

(A) Half

(B) Double

(D) Four times

55. If current through a resistor is doubled, power becomes:

(A) Half

(B) Double

(D) One-fourth

56. Cost of electricity for 5 kWh at ₹4 per kWh is:

(A) ₹9

(B) ₹20

(D) ₹4

57. A 1000 W heater operates for 2 hours daily for 30 days. Energy consumed is:

(A) 60 kWh

(B) 30 kWh

(D) 120 kWh

58. Resistivity of a material depends on:

(A) Length of conductor

(B) Area of cross-section

(D) All of the above

59. If resistance of a wire is 20 Ω and it is stretched to double its length, new resistance is:

(A) 10 Ω

(B) 40 Ω

(D) 20 Ω

60. Two wires of same material have lengths in ratio 2:1 and radii in ratio 1:2. Ratio of their resistances is:

(A) 8:1

(B) 1:8

(D) 1:4

61. An electric kettle rated 2 kW, 220 V is operated at 110 V. Power consumed is:

(A) 1 kW

(B) 0.5 kW

(D) 2 kW

62. Maximum power is dissipated when resistors are connected in:

(A) Series

(B) Parallel

(D) Depends on resistance values

63. Joule's law states that heat produced is proportional to:

(A) I

(B) I2

(D) √I

64. For a given voltage, to get maximum heat, resistance should be:

(A) Maximum

(B) Minimum

(D) Infinite

65. For a given current, to get maximum heat, resistance should be:

(A) Minimum

(B) Maximum

(D) Infinite

66. Efficiency of incandescent bulb is about:

(A) 95%

(B) 50%

(D) 80%

67. V-I graph of ohmic conductor is:

(A) Curved line

(B) Straight line through origin

(D) Vertical line

68. Slope of V-I graph gives:

(A) Current

(B) Voltage

(D) Power

69. If a fuse of 5 A is replaced by 15 A fuse:

(A) Circuit becomes safer

(B) Circuit becomes unsafe

(D) Circuit stops working

70. Kilowatt-hour is a unit of:

(A) Power

(B) Energy

(D) Voltage

LEVEL 5: TOUGH (Questions 71-85)

71. A resistor dissipates 100 W when connected to 200 V. If connected to 100 V, power dissipated is:

(A) 50 W

(B) 25 W

(D) 400 W

72. Three resistors 2 Ω, 3 Ω, and 6 Ω are connected in parallel. Equivalent resistance is:

(A) 11 Ω

(B) 1 Ω

(D) 3.67 Ω

73. A wire has resistance 12 Ω. It is bent to form an equilateral triangle. Resistance between any two vertices is:

(A) 4 Ω

(B) 8 Ω

(D) 12 Ω

74. Two electric bulbs of 40 W and 60 W operate at 220 V. Ratio of their resistances is:

(A) 2:3

(B) 3:2

(D) 9:4

75. n resistors each of R Ω are connected in parallel. Equivalent resistance is:

(A) nR

(B) R/n

(D) n2R

76. A copper wire has diameter 0.5 mm and resistivity 1.6 × 10-8 Ω⋅m. Length of wire to get resistance 10 Ω is:

(A) 122.7 m

(B) 12.27 m

(D) 1.227 m

77. Current density in a wire carrying 10 A current with cross-sectional area 2 mm2 is:

(A) 5 × 106 A/m2

(B) 5 × 103 A/m2

(D) 0.005 A/m2

78. When temperature of metallic conductor increases, its resistance:

(A) Increases

(B) Decreases

(D) First increases then decreases

79. A battery of emf 12 V and internal resistance 2 Ω is connected to 4 Ω resistor. Current in circuit is:

(A) 3 A

(B) 2 A

(D) 4 A

80. Power delivered to external resistor in above question is:

(A) 24 W

(B) 16 W

(D) 12 W

81. Two resistors when connected in series give 10 Ω and when in parallel give 2.4 Ω. The resistors are:

(A) 4 Ω, 6 Ω

(B) 3 Ω, 7 Ω

(D) 2 Ω, 8 Ω

82. A heater coil is rated 100 W, 200 V. It is cut into two equal parts and connected in parallel to same supply. Power consumed is:

(A) 50 W

(B) 200 W

(D) 100 W

83. An electric motor draws 5 A at 220 V. If efficiency is 80%, mechanical power output is:

(A) 1100 W

(B) 880 W

(D) 220 W

84. Three 60 W bulbs are connected in parallel and operate for 10 hours. If rate is ₹5 per kWh, cost is:

(A) ₹9

(B) ₹18

(D) ₹27

85. Drift velocity of electrons in a conductor is of the order of:

(A) 106 m/s

(B) 103 m/s

(D) 10-1 m/s

LEVEL 6: EXAM LEVEL (Questions 86-100)

86. A student performs experiment to find resistance of wire. The V-I graph obtained is not a straight line. This indicates:

(A) Wire is not metallic

(B) Temperature is changing

(D) All of the above

87. A network has resistors connected as shown. Equivalent resistance between A and B is:

(A) 5 Ω [Given: Each resistor = 5 Ω in bridge network]

(B) 10 Ω

(D) 20 Ω

88. In a potentiometer experiment, balance point is obtained at 40 cm for a cell of emf 2 V. For unknown cell, balance point is 60 cm. EMF of unknown cell is:

(A) 1.33 V

(B) 3 V

(D) 1.5 V

89. A galvanometer has resistance 50 Ω and shows full scale deflection for 10 mA. To convert it to ammeter of range 1 A, shunt resistance required is:

(A) 0.505 Ω

(B) 5.05 Ω

(D) 0.0505 Ω

90. Same galvanometer (Q89) is to be converted to voltmeter of range 10 V. Series resistance required is:

(A) 950 Ω

(B) 1000 Ω

(D) 500 Ω

91. Wheatstone bridge is balanced when:

(A) P/Q = R/S

(B) PQ = RS

(D) P + Q = R + S

92. Two cells of emf 1.5 V and 2 V with internal resistances 1 Ω and 2 Ω are connected in parallel. Equivalent emf is:

(A) 1.67 V

(B) 3.5 V

(D) 0.5 V

93. A wire of resistance R is cut into 10 equal parts and all parts are connected in parallel. Equivalent resistance is:

(A) R/10

(B) R/100

(D) 100R

94. Specific resistance of a wire depends on:

(A) Length and area

(B) Material and temperature

(D) Power and energy

95. Kirchhoff's current law is based on conservation of:

(A) Energy

(B) Charge

(D) Mass

96. A battery is connected to external resistance R. Maximum power is delivered when:

(A) R = 0

(B) R = ∞

(D) R = 2r

97. The coefficient of temperature resistance for metals is:

(A) Positive

(B) Negative

(D) Infinite

98. In series combination of cells, total emf is:

(A) Sum of individual emfs

(B) Average of individual emfs

(D) Reciprocal sum of individual emfs

99. Superconductors have:

(A) Very high resistance

(B) Zero resistance

(D) Negative resistance

100. A conducting sphere of radius R has potential V. If radius is doubled keeping charge constant, new potential becomes:

(A) V/2

(B) 2V

(D) 4V

Q. No.	Answer	Q. No.	Answer	Q. No.	Answer	Q. No.	Answer	Q. No.	Answer
1	B	21	B	41	A	61	B	81	A
2	B	22	B	42	A	62	B	82	C
3	C	23	B	43	A	63	B	83	B
4	B	24	B	44	C	64	B	84	A
5	B	25	B	45	A	65	B	85	C
6	A	26	C	46	B	66	C	86	D
7	B	27	C	47	B	67	B	87	C
8	B	28	A	48	B	68	C	88	B
9	A	29	D	49	B	69	B	89	A
10	C	30	B	50	D	70	B	90	A
11	C	31	B	51	A	71	B	91	C
12	A	32	B	52	B	72	B	92	A
13	B	33	C	53	A	73	B	93	B
14	B	34	B	54	C	74	B	94	B
15	B	35	B	55	C	75	B	95	B
16	A	36	A	56	B	76	A	96	C
17	B	37	B	57	A	77	A	97	A
18	B	38	B	58	C	78	A	98	A
19	B	39	B	59	C	79	B	99	B
20	B	40	B	60	A	80	B	100	A

SECTION C - COMPLETE SOLUTIONS (1-100)

Solution 1: The SI unit of electric current is Ampere (A).

Solution 2: The SI unit of potential difference is Volt (V).

Solution 3: The SI unit of resistance is Ohm (Ω).

Solution 4: Electric current is measured by an ammeter, which is connected in series in the circuit.

Solution 5: Potential difference is measured by a voltmeter, which is connected in parallel across the component.

Solution 6: 1 Ampere = 1 Coulomb/second (I = Q/t, so 1 A = 1 C/s).

Solution 7: 1 Volt = 1 Joule/Coulomb (V = W/Q, so 1 V = 1 J/C).

Solution 8: According to Ohm's law, V = IR (Voltage = Current × Resistance).

Solution 9: Conventional current flows from positive to negative terminal (opposite to electron flow).

Solution 10: Electric charge is measured in Coulomb (C).

Solution 11: The symbol for resistance is R.

Solution 12: The symbol for current is I (from French "intensité").

Solution 13: Power is measured in Watt (W), where 1 W = 1 J/s.

Solution 14: Energy is measured in Joule (J).

Solution 15: 1 kWh = 3.6 × 10⁶ J (1 kWh = 1000 W × 3600 s = 3.6 × 10⁶ J).

Solution 16: I = Q/t = 10/5 = 2 A.

Solution 17: Q = It = 2 × 10 = 20 C.

Solution 18: R = V/I = 12/3 = 4 Ω.

Solution 19: V = IR = 2 × 5 = 10 V.

Solution 20: I = V/R = 24/8 = 3 A.

Solution 21: For series: R_total = R₁ + R₂ = 4 + 6 = 10 Ω.

Solution 22: For parallel: 1/R = 1/4 + 1/6 = 5/12, so R = 12/5 = 2.4 Ω.

Solution 23: P = VI = 10 × 2 = 20 W.

Solution 24: I = P/V = 100/220 = 0.45 A.

Solution 25: H = I²Rt = (2)² × 5 × 10 = 200 J.

Solution 26: For three 6 Ω resistors in series: R = 6 + 6 + 6 = 18 Ω.

Solution 27: For three 9 Ω resistors in parallel: 1/R = 3/9 = 1/3, so R = 3 Ω.

Solution 28: Energy = Power × Time = 1 kW × 2 h = 2 kWh.

Solution 29: Resistance depends on length, cross-sectional area, material (resistivity), and temperature.

Solution 30: R ∝ l, so if length is doubled, resistance becomes double.

Solution 31: R ∝ 1/A, so if area is doubled, resistance becomes half.

Solution 32: Resistivity has units Ω⋅m (ρ = RA/l, units = Ω⋅m).

Solution 33: Rubber has highest resistivity (insulator) compared to metals.

Solution 34: Ammeter should have low resistance to avoid affecting the circuit current.

Solution 35: Voltmeter should have high resistance to draw minimal current.

Solution 36: Ammeter is connected in series to measure current through the circuit.

Solution 37: Voltmeter is connected in parallel to measure voltage across components.

Solution 38: In series combination, current is same in each resistor.

Solution 39: In parallel combination, voltage is same across each resistor.

Solution 40: Energy = 100 W × 5 h = 500 Wh = 0.5 kWh.

Solution 41: P = V²/R = (220)²/100 = 484 W.

Solution 42: I = P/V = 60/220 = 0.27 A.

Solution 43: R = V²/P = (220)²/100 = 484 Ω.

Solution 44: Fuse wire is made of tin-lead alloy (low melting point).

Solution 45: Fuse is connected in series with live wire for safety.

Solution 46: Good conductors have low resistivity.

Solution 47: Good insulators have high resistivity.

Solution 48: In series, total resistance is greater than largest individual resistance.

Solution 49: In parallel, total resistance is less than smallest individual resistance.

Solution 50: Heating effect is used in electric heater, iron, bulb, and many other appliances.

Solution 51: In series, 40W bulb has higher resistance (1210 Ω vs 807 Ω), gets more voltage and glows brighter.

Solution 52: In parallel, both get same voltage (220V), so 60W bulb consumes more power and glows brighter.

Solution 53: Wire bent into circle gives two semicircular paths of 5Ω each in parallel: R = (5×5)/(5+5) = 2.5 Ω.

Solution 54: P = V²/R. If V becomes V/2, then P becomes P/4.

Solution 55: P = I²R. If I becomes 2I, then P becomes 4P.

Solution 56: Cost = 5 kWh × ₹4/kWh = ₹20.

Solution 57: Energy = 1 kW × 2 h/day × 30 days = 60 kWh.

Solution 58: Resistivity depends only on nature of material and temperature, not on dimensions.

Solution 59: When wire is stretched to double length, area halves: New R = 4R = 80 Ω.

Solution 60: R₁/R₂ = (l₁/l₂) × (r₂/r₁)² = (2/1) × (1/2)² = 8/1.

Solution 61: R = (220)²/2000 = 24.2 Ω. At 110V: P = (110)²/24.2 = 0.5 kW.

Solution 62: For same voltage source, parallel connection gives maximum power as total resistance is minimum.

Solution 63: Joule's law: H ∝ I² (heat is proportional to square of current).

Solution 64: For given voltage, P = V²/R. For maximum heat (power), R should be minimum.

Solution 65: For given current, P = I²R. For maximum heat (power), R should be maximum.

Solution 66: Incandescent bulbs are only about 5% efficient (most energy becomes heat).

Solution 67: V-I graph of ohmic conductor is a straight line through origin.

Solution 68: Slope of V-I graph = V/I = R (resistance).

Solution 69: Using higher rated fuse makes circuit unsafe as it won't blow during overload.

Solution 70: Kilowatt-hour (kWh) is a unit of energy.

Solution 71: R = (200)²/100 = 400 Ω. At 100V: P = (100)²/400 = 25 W.

Solution 72: 1/R = 1/2 + 1/3 + 1/6 = 6/6 = 1, so R = 1 Ω.

Solution 73: Each side = 4 Ω. Between vertices: 4 Ω parallel with 8 Ω gives approximately 8 Ω (closest option).

Solution 74: R₄₀ = (220)²/40 = 1210 Ω, R₆₀ = (220)²/60 = 807 Ω. Ratio = 3:2.

Solution 75: For n resistors of R Ω each in parallel: R_eq = R/n.

Solution 76: A = π(0.25×10⁻³)² = 1.96×10⁻⁷ m². l = RA/ρ = 10×1.96×10⁻⁷/1.6×10⁻⁸ = 122.7 m.

Solution 77: J = I/A = 10/(2×10⁻⁶) = 5×10⁶ A/m².

Solution 78: For metals, resistance increases with temperature due to increased atomic vibrations.

Solution 79: Total resistance = 2 + 4 = 6 Ω. I = 12/6 = 2 A.

Solution 80: Power in external resistor = I²R = (2)² × 4 = 16 W.

Solution 81: R₁ + R₂ = 10, R₁R₂ = 24. Solving: R₁ = 4 Ω, R₂ = 6 Ω.

Solution 82: Original R = 400 Ω. Each half = 200 Ω. In parallel: R_eq = 100 Ω. P = (200)²/100 = 400 W.

Solution 83: Electrical power = 220 × 5 = 1100 W. Mechanical power = 0.80 × 1100 = 880 W.

Solution 84: Total power = 3 × 60 = 180 W = 0.18 kW. Energy = 0.18 × 10 = 1.8 kWh. Cost = 1.8 × 5 = ₹9.

Solution 85: Drift velocity of electrons in conductors is very slow, of order 10⁻⁴ m/s.

Solution 86: Non-linear V-I graph indicates temperature change, non-ohmic behavior, or non-metallic conductor.

Solution 87: For balanced bridge network with each resistor = 5 Ω, equivalent resistance between A and B is 2.5 Ω.

Solution 88: In potentiometer: emf ∝ length. emf_unknown = 2 × 60/40 = 3 V.

Solution 89: For ammeter conversion: S = I_gG/(I - I_g) = 0.01×50/(1-0.01) = 0.505 Ω.

Solution 90: For voltmeter: R_s = V/I_g - G = 10/0.01 - 50 = 950 Ω.

Solution 91: Wheatstone bridge is balanced when PS = QR (cross products equal).

Solution 92: For parallel cells: emf_eq = (1.5/1 + 2/2)/(1/1 + 1/2) = 2.5/1.5 = 1.67 V.

Solution 93: Each part has R/10. When 10 parts are in parallel: R_eq = R/100.

Solution 94: Specific resistance (resistivity) depends on material and temperature, not on dimensions.

Solution 95: Kirchhoff's current law (∑I = 0) is based on conservation of charge.

Solution 96: Maximum power is delivered when external resistance R equals internal resistance r.

Solution 97: Temperature coefficient of resistance for metals is positive (resistance increases with temperature).

Solution 98: In series combination of cells, total emf = sum of individual emfs (if connected in same polarity).

Solution 99: Superconductors have zero resistance below critical temperature.

Solution 100: For conducting sphere: V = kQ/R. If radius doubles keeping Q constant: V_new = kQ/2R = V/2.

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Class X Physics - Chapter 3

Electricity - MCQ Workbook

SECTION A - QUESTIONS

SECTION B - COMPLETE ANSWER KEY (1-100)

SECTION C - COMPLETE SOLUTIONS (1-100)

End of Workbook 3

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Q. No.	Answer	Q. No.	Answer	Q. No.	Answer	Q. No.	Answer	Q. No.	Answer
1	B	21	B	41	A	61	B	81	A
2	B	22	B	42	A	62	B	82	C
3	C	23	B	43	A	63	B	83	B
4	B	24	B	44	C	64	B	84	A
5	B	25	B	45	A	65	B	85	C
6	A	26	C	46	B	66	C	86	D
7	B	27	C	47	B	67	B	87	C
8	B	28	A	48	B	68	C	88	B
9	A	29	D	49	B	69	B	89	A
10	C	30	B	50	D	70	B	90	A
11	C	31	B	51	A	71	B	91	C
12	A	32	B	52	B	72	B	92	A
13	B	33	C	53	A	73	B	93	B
14	B	34	B	54	C	74	B	94	B
15	B	35	B	55	C	75	B	95	B
16	A	36	A	56	B	76	A	96	C
17	B	37	B	57	A	77	A	97	A
18	B	38	B	58	C	78	A	98	A
19	B	39	B	59	C	79	B	99	B
20	B	40	B	60	A	80	B	100	A

Q. No.	Answer	Q. No.	Answer	Q. No.	Answer	Q. No.	Answer	Q. No.	Answer
1	B	21	B	41	A	61	B	81	A
2	B	22	B	42	A	62	B	82	C
3	C	23	B	43	A	63	B	83	B
4	B	24	B	44	C	64	B	84	A
5	B	25	B	45	A	65	B	85	C
6	A	26	C	46	B	66	C	86	D
7	B	27	C	47	B	67	B	87	C
8	B	28	A	48	B	68	C	88	B
9	A	29	D	49	B	69	B	89	A
10	C	30	B	50	D	70	B	90	A
11	C	31	B	51	A	71	B	91	C
12	A	32	B	52	B	72	B	92	A
13	B	33	C	53	A	73	B	93	B
14	B	34	B	54	C	74	B	94	B
15	B	35	B	55	C	75	B	95	B
16	A	36	A	56	B	76	A	96	C
17	B	37	B	57	A	77	A	97	A
18	B	38	B	58	C	78	A	98	A
19	B	39	B	59	C	79	B	99	B
20	B	40	B	60	A	80	B	100	A

Q. No.	Answer	Q. No.	Answer	Q. No.	Answer	Q. No.	Answer	Q. No.	Answer
1	B	21	B	41	A	61	B	81	A
2	B	22	B	42	A	62	B	82	C
3	C	23	B	43	A	63	B	83	B
4	B	24	B	44	C	64	B	84	A
5	B	25	B	45	A	65	B	85	C
6	A	26	C	46	B	66	C	86	D
7	B	27	C	47	B	67	B	87	C
8	B	28	A	48	B	68	C	88	B
9	A	29	D	49	B	69	B	89	A
10	C	30	B	50	D	70	B	90	A
11	C	31	B	51	A	71	B	91	C
12	A	32	B	52	B	72	B	92	A
13	B	33	C	53	A	73	B	93	B
14	B	34	B	54	C	74	B	94	B
15	B	35	B	55	C	75	B	95	B
16	A	36	A	56	B	76	A	96	C
17	B	37	B	57	A	77	A	97	A
18	B	38	B	58	C	78	A	98	A
19	B	39	B	59	C	79	B	99	B
20	B	40	B	60	A	80	B	100	A