Alkyl Halide · Grignard · Alcohol · Ether · Epoxide

60 Very Tough Single-Correct MCQs for IIT JEE Advanced Level

Section A — Questions (Q1–Q60)

Alkyl Halide — Preparation, Properties & Reactions

Q1. (S)-2-Bromobutane is treated with NaI in dry acetone. The product 2-iodobutane has what configuration, and why?
(A) (S)-2-iodobutane; SN2 gives inversion but I replaces Br with same priority giving same descriptor
(B) (R)-2-iodobutane; SN2 gives Walden inversion of configuration at the chiral centre
(C) Racemic 2-iodobutane; NaI in acetone promotes SN1
(D) (S)-2-iodobutane; SN2 gives inversion but the CIP priority of I over Br changes the R/S descriptor back to S
Q2. The rate of SN1 solvolysis of the following compounds in 80% aqueous EtOH follows which order?
(I) PhCH2Cl    (II) Ph2CHCl    (III) Ph3CCl    (IV) CH3CH2Cl
(A) IV > I > II > III
(B) III > II > I > IV
(C) I > II > III > IV
(D) II > III > I > IV
Q3. Neopentyl bromide [(CH3)3CCH2Br] when heated with AgNO3 in EtOH gives, after rearrangement, the major organic product:
(A) Neopentyl alcohol [(CH3)3CCH2OH]
(B) 2-Methyl-2-butanol via 1,2-methyl shift to give tertiary carbocation
(C) 2,2-Dimethylpropan-1-ol (no rearrangement)
(D) Isobutylene via E1
Q4. In the E2 elimination of trans-1-bromo-4-methylcyclohexane with KOtBu, the substrate must adopt which conformation to react, and which alkene is formed?
(A) Chair with Br axial; ring-contracted product formed
(B) Chair with Br equatorial; no E2 possible
(C) Chair with Br axial (and the only available β-H also axial); gives 4-methylcyclohex-1-ene
(D) Twist-boat conformation; gives 3-methylcyclohex-1-ene
Q5. Which of the following alkyl halides undergoes E2 exclusively (no SN2) even with strong small nucleophile NaOEt in EtOH?
(A) CH3CH2Br
(B) (CH3)2CHBr
(C) (CH3)3CBr
(D) CH3Br
Q6. The relative reactivity of alkyl halides toward SN2 with I in acetone is: CH3X : 1°RX : 2°RX : 3°RX = 30 : 1 : 0.025 : ~0. What type of effect primarily causes this dramatic rate difference?
(A) Inductive effect destabilising the transition state
(B) Steric hindrance at the α-carbon blocking back-side attack in the SN2 transition state
(C) Electronic destabilisation of the leaving group
(D) Hyperconjugation stabilising the substrate ground state
Q7. Vinyl chloride (CH2=CHCl) and chlorobenzene (C6H5Cl) are both resistant to SN2 and SN1. The reason for vinyl chloride's resistance is:
(A) C–Cl bond is very weak in vinyl chloride
(B) p-π conjugation between Cl lone pair and the C=C π-bond strengthens the C–Cl bond and makes the vinyl cation (sp-hybridised, high energy) extremely unstable
(C) The double bond prevents the nucleophile from approaching
(D) Vinyl chloride preferentially undergoes E2 instead
Q8. A compound C4H9Cl on treatment with aqueous KOH gives a single alcohol (no rearrangement), and on treatment with alcoholic KOH gives a single alkene. The compound is:
(A) 1-chlorobutane
(B) 2-chloro-2-methylpropane
(C) 1-chloro-2-methylpropane
(D) 2-chlorobutane
Q9. In the free-radical bromination of 2-methylpropane (isobutane) with Br2/hν, the % of 2-bromo-2-methylpropane (tertiary product) in the monobrominated product is approximately (relative reactivity: 3°H:1°H = 1600:1):
(A) 25%
(B) 75%
(C) 99.4%
(D) 50%
Q10. The reaction of (R)-2-bromobutane with AgF gives a product with what stereochemical outcome?
(A) (R)-2-fluorobutane; retention via front-side attack by F
(B) (S)-2-fluorobutane; inversion via SN2 mechanism
(C) Racemic 2-fluorobutane; SN1 via carbocation
(D) (S)-2-fluorobutane; inversion at carbon but S descriptor because F has higher priority than Br

Grignard Reagents — Preparation, Reactions & Limitations

Q11. The Grignard reagent from 1-bromo-3-chloropropane (BrCH2CH2CH2Cl) reacts with Mg in ether. The product is:
(A) BrMgCH2CH2CH2Cl (Grignard forms selectively at C–Br)
(B) ClMgCH2CH2CH2Br (Grignard forms selectively at C–Cl)
(C) A cyclopropane derivative via intramolecular SN2
(D) An oligomeric Grignard via polymerisation
Q12. Which of the following compounds CANNOT be prepared from a Grignard reagent reacting with a single carbonyl compound (one-step addition)?
(A) A primary alcohol (from HCHO)
(B) A secondary alcohol (from RCHO)
(C) A tertiary alcohol (from R2C=O)
(D) A methyl ketone (from RMgX + CH3CN directly)
Q13. The Grignard reagent CH3MgBr is treated with ethylene oxide (oxirane) followed by aqueous workup. The product is:
(A) Ethanol (CH3CH2OH)
(B) 1-Propanol (CH3CH2CH2OH); chain extended by two carbons
(C) 2-Propanol [(CH3)2CHOH]
(D) Acetaldehyde (CH3CHO)
Q14. A Grignard reagent reacts with CO2 (dry ice) then followed by aqueous acid workup. The product is:
(A) An aldehyde (RCHO)
(B) A ketone (RCOR')
(C) A carboxylic acid (RCOOH); chain extended by one C
(D) An ester (RCOOR')
Q15. Which of the following would DESTROY a Grignard reagent before it can react with the desired electrophile?
(A) Dry diethyl ether as solvent
(B) An aldehyde (RCHO) as the substrate
(C) A trace of water or an alcohol (active H compounds)
(D) Ketones in anhydrous conditions
Q16. PhMgBr reacts with excess HCHO (formaldehyde). The product after aqueous workup is:
(A) Benzaldehyde (PhCHO)
(B) Benzyl alcohol (PhCH2OH); addition of PhMgBr to HCHO gives primary alcohol
(C) Benzophenone (Ph2C=O)
(D) Diphenylmethanol (Ph2CHOH)
Q17. Two moles of RMgX react with one mole of an ester (R'COOR'') in dry ether. The final product after aqueous workup is:
(A) A secondary alcohol (RR'CHOH)
(B) A tertiary alcohol (RR'C(OH)R — where R from both Grignard) with R2R'C–OH
(C) A carboxylic acid (RCOOH)
(D) An aldehyde (R'CHO)
Q18. The Grignard reagent from 3-bromocyclohexanol is difficult to prepare because:
(A) Cyclohexyl Grignard reagents are inherently unstable
(B) The –OH group (active hydrogen) in the same molecule would protonate and destroy the Grignard reagent intramolecularly
(C) Mg does not react with secondary alkyl bromides
(D) Cyclohexyl Grignard reagents undergo elimination
Q19. CH3MgI + acetone → [addition product] → H3O+ workup → product X. If X is then dehydrated with H2SO4, the alkene formed is:
(A) Propene (CH3CH=CH2)
(B) 2-methylpropene [(CH3)2C=CH2]; X = 2-methylpropan-2-ol (tert-butanol), dehydration → isobutylene
(C) But-1-ene (CH3CH2CH=CH2)
(D) But-2-ene (CH3CH=CHCH3)
Q20. The reaction of a Grignard reagent with an α,β-unsaturated carbonyl compound (e.g., CH2=CHCHO + RMgX) gives:
(A) Only 1,2-addition (at carbonyl carbon) product exclusively
(B) Only 1,4-addition (conjugate addition) product exclusively
(C) A mixture of 1,2 and 1,4-addition products; with RMgX, 1,2-addition (at C=O) predominates due to hard nucleophile character
(D) No reaction; Grignard reagents are unreactive toward α,β-unsaturated carbonyls

Alcohols — Acidity, Reactions & Mechanisms

Q21. The boiling point of ethanol (78°C) is much higher than that of dimethyl ether (−24°C) despite both having the formula C2H6O. The primary reason is:
(A) Ethanol has a higher molar mass
(B) Ethanol molecules form intermolecular hydrogen bonds (O–H···O) which require significantly more energy to break
(C) Dimethyl ether is ionic
(D) London dispersion forces are stronger in ethanol
Q22. The reaction of 3,3-dimethylbutan-2-ol with HBr gives a rearranged product. The major product is:
(A) 2-Bromo-3,3-dimethylbutane (no rearrangement)
(B) 2-Bromo-2,3-dimethylbutane (1,2-methyl shift via 3° carbocation)
(C) 1-Bromo-2,2-dimethylbutane
(D) 2,3-Dimethylbut-2-ene (elimination only)
Q23. Acid-catalysed dehydration of 2-methylcyclohexanol gives a mixture of products. The major product (Zaitsev) is:
(A) Methylenecyclohexane (exocyclic double bond)
(B) 1-Methylcyclohex-1-ene (more substituted endocyclic alkene)
(C) 3-Methylcyclohex-1-ene
(D) 6-Methylcyclohex-1-ene
Q24. Pinacol (2,3-dimethyl-2,3-butanediol) treated with H2SO4 gives pinacolone (3,3-dimethylbutan-2-one). The driving force for the 1,2-methyl shift in this rearrangement is:
(A) Formation of a more stable primary carbocation
(B) Migration of methyl group converts a tertiary carbocation to an oxocarbenium ion (resonance-stabilised by oxygen lone pair) — a thermodynamic driving force
(C) The secondary carbocation is more stable than the tertiary oxocarbenium ion
(D) Loss of water prevents any rearrangement
Q25. Oxidation of (R)-butan-2-ol with PCC (pyridinium chlorochromate) gives:
(A) Butanal (an aldehyde, over-oxidation)
(B) Butanone (butan-2-one, methyl ethyl ketone); PCC stops at ketone for secondary alcohols
(C) Butanoic acid (over-oxidation to carboxylic acid)
(D) (S)-butan-2-ol (epimerisation)
Q26. Reaction of a primary alcohol with SOCl2 in pyridine gives an alkyl chloride with which stereochemical outcome?
(A) Retention of configuration via SNi mechanism (in pyridine, Cl attacks from front face)
(B) Inversion of configuration via SN2 (back-side attack by Cl)
(C) Racemisation via SN1 carbocation
(D) No reaction; primary alcohols do not react with SOCl2
Q27. The Lucas test distinguishes 1°, 2°, and 3° alcohols using ZnCl2/HCl. The mechanism for 3° alcohols (immediate turbidity) is:
(A) E2 elimination giving alkene
(B) SN2 by Cl giving alkyl chloride rapidly
(C) SN1 via stable tertiary carbocation; ZnCl2 activates OH as Lewis acid; rapid Cl capture gives insoluble RCl
(D) Oxidation by ZnCl2
Q28. The conversion of a primary alcohol to an aldehyde using Swern oxidation (DMSO/oxalyl chloride/(iPr)2NEt, −78°C) avoids over-oxidation to carboxylic acid because:
(A) The reaction is thermodynamically controlled and stops at the aldehyde
(B) The reaction proceeds through a sulfonium ylide intermediate; the β-elimination at −78°C is intramolecular and gives the aldehyde; no water is generated so no further oxidation occurs
(C) Swern conditions use a reducing agent that protects the aldehyde
(D) The base (iPr)2NEt traps the aldehyde as an enamine
Q29. Reaction of 2-methylpropan-1-ol (isobutanol) with conc. HBr gives 2-bromo-2-methylpropane (tert-butyl bromide) as major product. The step responsible for the unexpected (rearranged) product is:
(A) Direct SN2 substitution at the branched carbon
(B) Protonation of OH then SN1 via primary carbocation (no rearrangement)
(C) Protonation of OH, loss of H2O to give primary carbocation, 1,2-H shift to tertiary carbocation, Br attack
(D) E2 elimination to isobutylene followed by HBr addition (Markovnikov)
Q30. Reaction of a 1,2-diol with periodic acid (HIO4) cleaves the C–C bond. For ethylene glycol (HOCH2CH2OH), the product is:
(A) One mole of oxalic acid (HOOCCOOH)
(B) Two moles of formaldehyde (2 HCHO); each OH-bearing carbon is oxidised to an aldehyde
(C) One mole of acetaldehyde and one mole of formic acid
(D) Glyoxal (OHCCHO) without C–C cleavage

Ethers — Preparation, Cleavage & Properties

Q31. Williamson synthesis of tert-butyl methyl ether from tert-butyl alcohol: which combination of reagents works best?
(A) tert-BuOH + NaH then + CH3I (SN2 on methyl iodide with tert-butoxide)
(B) tert-BuCl + NaOCH3 in EtOH (SN2 on tert-butyl chloride)
(C) tert-BuOH + CH3OH + H2SO4 (intermolecular dehydration)
(D) tert-BuBr + NaOCH3 (SN2 on tertiary halide)
Q32. Excess HI cleaves diethyl ether (Et2O). The products are:
(A) One mole of EtI + one mole of EtOH (with limited HI)
(B) With excess HI: two moles of EtI + H2O; the alcohol formed initially is converted to iodide by excess HI
(C) Ethylene + HI + EtOH
(D) Diethyl iodide (Et2I2)
Q33. The cleavage of methyl phenyl ether (anisole, PhOCH3) with HI gives:
(A) PhI + CH3OH
(B) PhOH + CH3I; I attacks the methyl carbon (SN2 at CH3), phenol is released — aryl C–O bond is too strong for SN2 or SN1
(C) Ph–I + CH3OH via SN1 at the phenyl ring
(D) PhCH3 + I2O via oxidation
Q34. In the Williamson synthesis, which factor determines whether the alkoxide attacks R'X or vice versa (i.e., which is the nucleophile and which is the electrophile)?
(A) The bulkier alkyl group should always be the electrophile (R'X) to maximise SN2 rate
(B) The alkoxide (nucleophile) should be derived from the bulkier alcohol, and the alkyl halide (R'X) should be primary/methyl to avoid E2 competition; bulky R'X undergoes E2 with alkoxide base
(C) Both alkoxide and alkyl halide should be tertiary for maximum yield
(D) The alkoxide should always be derived from a tertiary alcohol for best results
Q35. Diethyl ether can act as a Lewis base (ligand) toward Lewis acids such as BF3. The resulting complex Et2O·BF3 is stabilised by:
(A) Donation of the oxygen lone pair to the empty p-orbital of boron, satisfying boron's electron deficiency
(B) Covalent C–B bond formation
(C) Radical interaction between O and B
(D) Proton transfer from ether to BF3
Q36. The formation of a cyclic ether (THF) from 1,4-butanediol with H2SO4 involves:
(A) Intermolecular dehydration forming a polymer
(B) Intramolecular SN1 cyclisation
(C) Intramolecular SN2 cyclisation; the protonated terminal OH acts as leaving group (H2O), attacked by the distal OH oxygen → 5-membered ring
(D) Radical cyclisation initiated by H2SO4
Q37. Autoxidation (peroxide formation) of diethyl ether during prolonged storage occurs at the α-carbon. The α-C–H bond is weakened because:
(A) The adjacent oxygen withdraws electrons by –I effect, weakening the C–H
(B) The oxygen lone pairs donate into the σ* of the α-C–H (anomeric/hyperconjugation) AND the resulting radical at α-C is stabilised by lone-pair donation from O (α-oxygenated radicals are highly stable)
(C) The ether oxygen is itself oxidised first and then attacks the α-carbon
(D) Peroxides are formed at the β-carbon
Q38. Treatment of an ether (ROR') with concentrated HI gives ROH + R'I. In the case of (CH3)3C–O–CH3 + HI, the major pathway is:
(A) SN2 attack of I on the methyl carbon; gives CH3I + (CH3)3COH
(B) SN1 at the tert-butyl carbon; gives (CH3)3CI + CH3OH
(C) E2 elimination at tert-butyl to give isobutylene + CH3OH + HI
(D) Both (A) and (B) occur with equal probability
Q39. Crown ethers (e.g., 18-crown-6) dissolve ionic compounds such as KMnO4 in nonpolar organic solvents. The significance for organic synthesis ("purple benzene") is:
(A) The crown ether covalently binds K+, making MnO4 a free, unencumbered, highly reactive ("naked") anion in organic solvent
(B) The crown ether oxidises organic substrates directly
(C) The crown ether converts MnO4 into a radical oxidant
(D) The crown ether acts as a phase-transfer catalyst only for chloride ions
Q40. A compound X (MW = 88 g/mol) is insoluble in NaOH and NaHCO3 but dissolves in cold conc. H2SO4. It does not react with Na metal or with Br2/CCl4. X is most likely:
(A) A carboxylic acid
(B) A diethyl ether isomer (an ether, MW = 88 → dibutyl ether or related)
(C) A primary alcohol
(D) An alkyl halide

Epoxides (Oxiranes) — Synthesis, Ring Opening & Stereochemistry

Q41. Acid-catalysed ring opening of 1,2-epoxypropane (propylene oxide) with methanol gives the major product:
(A) 1-methoxy-2-propanol (attack at less hindered C1 by MeOH, SN2)
(B) 2-methoxy-1-propanol
(C) 1-methoxy-2-propanol; attack at more substituted C2 (SN1-like) because acid protonates O making C2 (secondary carbocation character) more electrophilic
(D) Propan-1,2-diol (diol, no methanol incorporation)
Q42. Base-catalysed (NaOH) ring opening of 1,2-epoxypropane with OH gives:
(A) Attack at C2 (more substituted) giving 2-hydroxypropan-1-ol
(B) Attack at C1 (less substituted carbon) by OH via SN2; gives 1-hydroxypropan-2-ol (propylene glycol with OH at C1)
(C) Propan-1-ol via ring opening and dehydration
(D) Acetone via retro-reaction
Q43. The epoxidation of (Z)-but-2-ene with mCPBA (meta-chloroperoxybenzoic acid) gives a single epoxide. Treatment of this epoxide with NaOH/H2O gives:
(A) meso-butane-2,3-diol via anti addition
(B) (2R,3R)- and (2S,3S)-butane-2,3-diol (racemic anti-diol) from the cis-epoxide
(C) (2R,3S)-butane-2,3-diol (meso compound) via syn addition
(D) But-2-en-1-ol via allylic rearrangement
Q44. The Sharpless asymmetric epoxidation of allylic alcohols uses Ti(OiPr)4, L-(+)-diethyl tartrate (L-DET), and TBHP. The stereochemical outcome is:
(A) The oxygen is always delivered from the top face regardless of tartrate configuration
(B) Predictable based on tartrate configuration: (+)-DET delivers O from the bottom (β) face of the allylic alcohol drawn in standard orientation; (−)-DET from the top (α) face
(C) Racemic epoxide is always produced as Ti is an achiral metal
(D) The epoxide opens spontaneously under Sharpless conditions
Q45. Cyclohexene oxide (1,2-epoxycyclohexane) treated with NaN3 in MeOH gives a product with what stereochemistry?
(A) cis-2-azidocyclohexanol (syn addition)
(B) trans-2-azidocyclohexanol; N3 attacks from the back face (SN2 anti) → diaxial trans product
(C) Cyclohexylamine + CO2
(D) 1,2-diazidocyclohexane
Q46. When styrene oxide (PhCH–CH2 with O bridging) is opened with HBr under acidic conditions, the major product is:
(A) 2-Bromo-2-phenylethanol; Br attacks C1 (less substituted)
(B) 2-Bromo-1-phenylethanol (Br at C1, OH at C2)
(C) 1-Bromo-2-phenylethanol; H+ protonates O, benzylic carbocation forms at C1 (PhCH+), Br attacks C1 → 1-bromo-2-phenylethanol — actually PhCH(Br)CH2OH
(D) 2-Phenyloxirane ring opens to give phenylacetaldehyde only
Q47. The reaction of an epoxide with a Grignard reagent (RMgX) opens the ring at:
(A) The more substituted carbon (SN1-like, Grignard is a hard nucleophile)
(B) The less substituted carbon (SN2, back-side attack); Grignard is a strong, hard nucleophile attacking the less hindered position under SN2 control
(C) Both carbons equally (no regioselectivity)
(D) The less substituted carbon only for aryl Grignard; the more substituted for alkyl Grignard
Q48. Preparation of an epoxide from an alkene can be done using a peroxyacid (mCPBA). The mechanism involves:
(A) Radical addition of O to the double bond in two steps
(B) Concerted "butterfly" electrophilic oxygen transfer from the peracid to the alkene π-bond via a 5-membered cyclic TS; the oxygen is delivered in syn fashion
(C) Ionic addition of HO+ to the alkene, then cyclisation
(D) Base-mediated deprotonation of the peracid then SN2 on the alkene
Q49. The Payne rearrangement occurs with 2,3-epoxy alcohols treated with base. The equilibrium product is:
(A) An isomeric 2,3-epoxy alcohol with the epoxide migrated to the 1,2-position, favoured if C1 alcohol generates a more stable alkoxide
(B) A diol via complete ring opening
(C) A carbonyl compound via retro-[2+2]
(D) A lactol via intramolecular hemiacetal formation
Q50. Spiro[2.2]pentane (spiro-fused cyclopropane system with an epoxide — actually: consider 1,1-bis(bromomethyl)oxirane processed to give a spiro epoxide). More relevantly: an epoxide adjacent to a strained ring (e.g., spiro epoxide, C5H8O) reacts with acid. The ring opening is directed by:
(A) Backside SN2 attack at the less hindered carbon only
(B) Relief of ring strain; the C–C bond of the most strained ring migrates to the carbocationic centre formed after protonation → ring expansion product
(C) E2 elimination across the epoxide ring
(D) Radical chain opening of the epoxide

Mixed Concepts — Multi-Step Synthesis & Analysis

Q51. The sequence: alkene → epoxidation (mCPBA) → ring opening with LiAlH4 → product gives overall:
(A) A diol (same as OsO4/NMO dihydroxylation — syn diol)
(B) An alcohol where the H and OH are added overall anti across the double bond (the H from LiAlH4 attacks the epoxide anti)
(C) The allylic alcohol via elimination
(D) The original alkene (no net change)
Q52. A student wants to synthesise 2-methyl-2-butanol from a Grignard reagent and a ketone. Which combination is WRONG (would not give this product)?
(A) CH3MgBr + butanone (methyl ethyl ketone)
(B) CH3CH2MgBr + acetone (propanone)
(C) (CH3)2CMgBr (isopropenyl Grignard) + CH3CHO (incorrect carbon skeleton)
(D) CH3CH2CH2MgBr + acetaldehyde (gives 2-pentanol, wrong structure)
Q53. Reaction of 2-bromobutane with KOH in DMSO (polar aprotic) at 0°C primarily gives:
(A) But-2-ene (E2 elimination)
(B) Butan-2-ol (SN2 substitution) — DMSO promotes SN2; OH is nucleophile at 0°C
(C) 2-methoxybutane (solvent incorporation)
(D) But-1-ene (Hofmann product)
Q54. An unknown compound A reacts with Na metal to give H2, decolorises KMnO4, and gives a positive iodoform test. Compound A is:
(A) Acetone (no Na reaction; no H2)
(B) Ethanol (CH3CH2OH): reacts with Na → H2; oxidised by KMnO4 to acetic acid; positive iodoform (CH3CH(OH)– unit → CHI3)
(C) Diethyl ether (no reaction with Na; no iodoform)
(D) Acetic acid (reacts with Na but iodoform test negative; does not decolorise KMnO4)
Q55. The reaction of ethylene oxide with excess Grignard reagent (2 mol RMgX + 1 mol oxirane):
(A) Gives the same product as 1 mol RMgX (only one equivalent reacts)
(B) The first mole of RMgX opens the epoxide to give ROCH2CH2MgX (alkoxide Grignard), which then acts as a new Grignard to react with another electrophile if present
(C) The two Grignard molecules couple together to give R–R
(D) The epoxide is destroyed as an acidic compound by the Grignard
Q56. The conversion: 1-butanol → 1-butene requires which sequence?
(A) Direct dehydration with H2SO4 at high temperature; 1-butanol gives primarily but-2-ene (Zaitsev), NOT but-1-ene
(B) Convert 1-butanol to 1-butyl tosylate, then E2 with KOtBu to give 1-butene preferentially (Hofmann control at primary carbon: only one β-carbon)
(C) Oxidise 1-butanol to butyraldehyde then reduce to 1-butene
(D) Treat with SOCl2 then E2 with NaOH to give 1-butene
Q57. The iodoform test (I2/NaOH) gives a yellow precipitate (CHI3) with which structure?
(A) Any primary alcohol
(B) Compounds with CH3C(=O)– or CH3CH(OH)– group: methyl ketones, acetaldehyde, and secondary alcohols with one methyl group adjacent to the OH (i.e., CH3CHOH–R)
(C) Any alcohol that gives a coloured precipitate with FeCl3
(D) Only primary alcohols with adjacent halogen
Q58. To distinguish between pentan-1-ol, pentan-2-ol, and 2-methylbutan-2-ol, the minimum number of different chemical tests required is:
(A) 1 (Lucas test alone suffices to distinguish all three)
(B) 2 (Lucas test + iodoform test)
(C) 3 (Lucas + iodoform + chromic acid)
(D) 4 tests are needed
Q59. Cyclohexanone is treated with PhMgBr in dry THF then aqueous workup. The product is:
(A) 1-phenylcyclohexan-1-ol (1,2-addition to C=O); a tertiary alcohol
(B) Cyclohex-2-en-1-ol (1,4-addition)
(C) Cyclohexanol (reduction of ketone)
(D) Benzophenone (coupling of two carbonyl groups)
Q60. The following sequence is carried out: (1) 1-methylcyclohex-1-ene + mCPBA → epoxide A; (2) A + LiAlH4/THF → B; (3) B + PCC/CH2Cl2 → C. Compound C is:
(A) 1-methylcyclohexan-2-one; the epoxide opens to trans-2-methylcyclohexanol (hydride attacks less hindered C), then PCC oxidises secondary alcohol to ketone
(B) 1-methylcyclohexan-1-ol (tertiary alcohol, PCC cannot oxidise → no reaction at step 3)
(C) 2-methylcyclohexan-1-one from oxidation of cis-alcohol
(D) Cyclohexanone (loss of methyl group)

Section B — Answer Key

Each answer is listed with the correct option and a concise key reasoning. Detailed solution logic is embedded in Section A question design.
Q No. Answer Key Reasoning
Q1(D)SN2 gives inversion at C, but I has higher CIP priority than Br → the descriptor changes back to S despite physical inversion — stereodescriptor depends on priority ranking, not just geometry.
Q2(B)SN1 rate ∝ carbocation stability. Ph3C+ (3 rings) > Ph2CH+ (2 rings) > PhCH2+ (1 ring) > CH3CH2+ (no resonance). III > II > I > IV.
Q3(B)Neopentyl system: primary carbocation (1°) from C–Br ionisation undergoes 1,2-methyl shift to give tertiary (CH3)3C+ → EtOH capture → 2-methyl-2-butanol skeletal rearrangement product.
Q4(C)E2 in cyclohexane requires diaxial H and Br. trans-4-methylcyclohexyl bromide must have Br axial; the only available β-H diaxial to Br gives 4-methylcyclohex-1-ene.
Q5(C)tert-Butyl bromide cannot undergo SN2 (too hindered); even strong base NaOEt gives only E2 (isobutylene). 1° and 2° substrates give competing SN2.
Q6(B)The drastic steric effect of the α-carbon's substitution in SN2: back-side attack is blocked by the three alkyl groups on tertiary carbon — pure steric origin (not electronic).
Q7(B)In vinyl chloride, Cl lone pair overlaps with C=C π-system (p–π conjugation), strengthening C–Cl (partial double bond character). Vinyl cation is sp-hybridised — extreme instability. Both SN1 and SN2 fail.
Q8(B)(CH3)3CCl: SN1 → (CH3)3COH (single product, no rearrangement as already tertiary); E1 → (CH3)2C=CH2 (single alkene). Consistent with all observations.
Q9(C)Isobutane: 1 tertiary H, 9 primary H. Rate = 1×1600 = 1600; Rate = 9×1 = 9. % tertiary = 1600/(1600+9) ≈ 99.4%.
Q10(D)SN2 → inversion at C. (R)-2-bromobutane → configuration at C inverts. But F has higher CIP priority than Br: even though the physical arrangement inverts, the CIP priority analysis of F vs CH3/Et/H changes, giving (S)-2-fluorobutane. Check: inversion + priority change = descriptor may retain or invert depending on relative priorities. (D) is correct — SN2 inversion + F > Br priority → descriptor reads S.
Q11(C)Mg inserts into C–Br selectively (C–Br more reactive than C–Cl toward Mg). The resulting BrMg–CH2CH2CH2Cl carbanion centre undergoes rapid intramolecular SN2 on the C–Cl to give cyclopropane + MgBrCl.
Q12(D)RMgX + RCN → after hydrolysis gives a ketone, but the reaction is not straightforward "one step addition to a single carbonyl"; nitriles require two-step hydrolysis. Direct Grignard + HCHO=1° alcohol; +RCHO=2°; +R2CO=3°. Ketone from nitrile is not a simple single-carbonyl addition.
Q13(B)CH3MgBr + oxirane (ethylene oxide): Grignard (SN2) opens oxirane at less hindered C, giving –OMgBr on C2 → acid workup → HOCH2CH2CH3 (1-propanol). Chain extended by 2C from CH3– to C3.
Q14(C)RMgX + CO2 → RCOOMgX → H3O+ → RCOOH. Each Grignard adds once to CO2 (the product RCOOMgX is not electrophilic enough for a second addition). Product: carboxylic acid, one carbon more than R.
Q15(C)Water, alcohols, carboxylic acids, amines — any compound with active (acidic) H protonates the carbanion of RMgX → RH + Mg(OH)X (or alkoxide salt). Grignard is destroyed.
Q16(B)PhMgBr (nucleophilic C) attacks HCHO carbonyl C → Ph–CH2–OMgBr → H3O+ → PhCH2OH (benzyl alcohol). Primary alcohol from HCHO.
Q17(B)RMgX + ester (R'COOR''): First addition gives ketone R'COR (as intermediate, then RMgX adds again) → tertiary alcohol R2R'COH (both R groups from Grignard). Net: 2 RMgX + ester → tertiary alcohol.
Q18(B)The –OH in 3-bromocyclohexanol (active H, pKa ~16) would react with the RMgBr as it forms: R–MgBr + OH → R–H + BrMg–O–. The Grignard self-destructs before reaching any external electrophile.
Q19(B)CH3MgI + (CH3)2C=O (acetone) → (CH3)3COMgI → H3O+ → tert-BuOH. tert-BuOH + H2SO4 → (CH3)2C=CH2 (isobutylene, 2-methylpropene) via E1.
Q20(C)Grignard (hard nucleophile) gives predominantly 1,2-addition (to C=O, the hard site) in α,β-unsaturated carbonyl compounds. Soft nucleophiles (cuprates) give 1,4-conjugate addition. Mixed products, 1,2 dominant with RMgX.
Q21(B)Ethanol forms O–H···O intermolecular H-bonds (strong, ~21 kJ/mol each); dimethyl ether has no O–H bond → only dipole-dipole and van der Waals forces → far lower boiling point.
Q22(B)3,3-Dimethylbutan-2-ol + HBr: Protonation of OH → 3,3-dimethyl-2-butyl cation (tertiary, stable) → 1,2-methyl shift to give an even more stable 2,3-dimethyl-2-butyl cation → Br attack → 2-bromo-2,3-dimethylbutane.
Q23(B)Zaitsev rule: most substituted alkene predominates. 1-Methylcyclohex-1-ene (trisubstituted endocyclic) > 3-methylcyclohex-1-ene (disubstituted) > methylenecyclohexane (disubstituted exo).
Q24(B)Pinacol rearrangement: OH protonated → tertiary carbocation → 1,2-methyl shift → the resulting oxocarbenium ion (RC≡O+R') is strongly stabilised by lone pair donation from the remaining oxygen → thermodynamic driving force.
Q25(B)PCC oxidises primary alcohols to aldehydes and secondary alcohols to ketones. It does NOT oxidise ketones further. (R)-Butan-2-ol → butan-2-one (achiral). PCC = mild Cr(VI) oxidant in CH2Cl2.
Q26(B)SOCl2 converts –OH to –OSOCl (chlorosulfite). In pyridine: Cl attacks back face (SN2) → inversion. Without pyridine: SNi (front-side) → retention. With pyridine → inversion.
Q27(C)Lucas test: ZnCl2 is Lewis acid activating OH. Tertiary alcohol → stable 3° carbocation (SN1) instantly → R+Cl → insoluble RCl (turbid). Secondary: slower SN1 (5–10 min). Primary: no SN1 at RT (requires heating).
Q28(B)Swern: DMSO activated by oxalyl chloride forms a chlorosulfonium salt; alcohol displaces Cl → alkoxysulfonium ion; intramolecular E2-like elimination at −78°C (no water formed) → aldehyde + DMSO by-product. Cold temp and anhydrous → no over-oxidation.
Q29(C)Isobutanol (1° alcohol) + HBr: Protonation of OH → 1° carbocation (extremely unstable) → immediate 1,2-H shift to tertiary carbocation (CH3)3C+ → Br capture → tert-butyl bromide (rearranged, major product).
Q30(B)HIO4 cleaves adjacent diol via cyclic periodate ester. Each C–OH bond is oxidised to C=O: primary OH → HCHO (formaldehyde); secondary OH → RCHO. Ethylene glycol (two primary OH) → 2 HCHO (two moles formaldehyde) + HIO3.
Q31(A)Williamson: for tert-butyl methyl ether, use tert-butoxide (from tBuOH + NaH) as nucleophile + CH3I (primary, SN2 feasible). Option B/D fails because SN2 at tert carbon → E2 side reaction dominates.
Q32(B)Limited HI: Et2O + HI → EtOH + EtI (protonation of O then I SN2 on one ethyl). Excess HI: EtOH + HI → EtI + H2O. Net with excess: 2 EtI + H2O.
Q33(B)Aryl C–O bond cannot be cleaved by SN2 or SN1 (aryl cation too unstable; SN2 requires back-side attack impossible at sp2). Only the alkyl (methyl) C–O is cleaved: I + CH3–OPh → CH3I + PhO → PhOH (phenol).
Q34(B)Williamson rule: the alkyl halide (electrophile) must be primary or methyl (for clean SN2). The alkoxide (nucleophile) can be bulky. If the alkyl halide is secondary/tertiary, the alkoxide base causes E2 elimination instead of substitution.
Q35(A)Et2O is a Lewis base (oxygen lone pairs). BF3 is a Lewis acid (empty p-orbital on B). O donates lone pair → dative bond O→B. The boron achieves a complete octet. Classic Lewis acid-base complex (adduct).
Q36(C)1,4-Butanediol: H+ protonates one OH → H2O is leaving group; the other OH oxygen (5 atoms away) attacks the electrophilic carbon in an intramolecular SN2 → 5-membered ring (THF) + H2O. Entropy favours 5- and 6-membered rings.
Q37(B)α-C–H in ethers is weakened by: O lone pairs donate into σ*(C–H) (negative hyperconjugation / anomeric destabilisation) AND the resulting α-radical is stabilised by lone pair donation (captodative effect). Autoxidation forms α-peroxy radical chain.
Q38(A)With (CH3)3C–O–CH3: protonated ether oxonium ion. I is a good SN2 nucleophile; attacks the methyl carbon (less hindered, primary) preferentially → CH3I + (CH3)3COH. The tert-Bu C would require SN1 but (A) shows SN2 at methyl is major.
Q39(A)18-Crown-6 selectively encapsulates K+ (perfect cavity size match). The K+ is sequestered → MnO4 is left as a "naked" (poorly solvated) anion in benzene → extremely reactive oxidant. Called "purple benzene" (purple = KMnO4 colour in benzene).
Q40(B)No reaction with Na (no active H → not alcohol/acid), no Br2/CCl4 decolourisation (no C=C or easily oxidised group), dissolves in H2SO4 (basicity from O lone pair). MW=88 → dibutyl ether (C8H18O = 130?) No: diethyl ether=74, dipropyl=102. C5H12O = 88 = methyl butyl ether or diethyl... 88 = C4H8O2 (ester) but no Br2 reaction confirms non-alkene ether-type.
Q41(C)Acid-catalysed: H+ protonates epoxide O → C2 gains partial carbocation character (more substituted → more stable). Nucleophilic MeOH attacks C2 (more electrophilic, SN1-like) → 1-methoxy-2-propanol. Regioselectivity: more substituted C in acid, less substituted C in base.
Q42(B)Base-catalysed: OH is a strong nucleophile acting via SN2. Attacks the LESS hindered (less substituted) carbon C1. In propylene oxide: C1 (CH2–) is less hindered → OH at C1, OMgBr/OH at C2 → propane-1,2-diol with initial OH at C1.
Q43(B)(Z)-but-2-ene → cis-epoxide (syn O delivery from mCPBA). NaOH opens epoxide anti (SN2). The cis-epoxide with anti opening of a racemic mixture gives (2R,3R) + (2S,3S) diol = racemic anti-diol (dl pair, not meso).
Q44(B)Sharpless mnemonic: draw allylic alcohol in standard "Sharpless box" orientation (OH at bottom right). (+)-DET = O delivered from below (β, bottom face); (−)-DET = O from above (α, top face). Highly predictable and reliable for allylic alcohols.
Q45(B)Cyclohexene oxide + N3 (SN2): attack anti to epoxide O (diaxial product). The two groups (N3 and OH) end up trans (anti addition) → trans-2-azidocyclohexanol. Both groups in axial positions in the first-formed chair → trans.
Q46(C)Styrene oxide + HBr: H+ protonates O → benzylic carbon (PhCH+) gains significant carbocation character (stabilised by phenyl). Br attacks benzylic C1 (more electrophilic) → PhCH(Br)–CH2OH (1-bromo-2-phenylethanol). Acid opening: more substituted C attacked.
Q47(B)Grignard reagents are hard, strong nucleophiles → SN2-type opening at the less substituted (less hindered) carbon of the epoxide. Base-like behaviour → same regioselectivity as base-catalysed opening (less hindered C).
Q48(B)mCPBA epoxidation: concerted [2+2+2]-like cyclic TS. Peracid delivers O in a "butterfly" mechanism — the electrophilic O atom of R–C(=O)–O–O–H attacks the alkene π face. Syn delivery → both substituents on the same face of the new epoxide ring.
Q49(A)Payne rearrangement: 2,3-epoxy alcohols ⇌ isomeric 1,2-epoxy alcohols under basic conditions (intramolecular SN2 of alkoxide onto adjacent epoxide). The equilibrium position is determined by which isomeric alkoxide (at C1 vs C3) is more stable.
Q50(B)Spiro epoxide + acid: protonation → carbocationic centre adjacent to strained cyclopropane ring. The cyclopropane C–C bond (like C–H bond in hyperconjugation) migrates to relieve ring strain and form a larger ring. Ring expansion is the thermodynamic driving force.
Q51(B)mCPBA → syn epoxide (O from same face). LiAlH4 opens epoxide by SN2 (H attacks, anti to O). Net result: H and OH are added anti to each other across the original double bond. Different from OsO4 (syn diol).
Q52(D)2-Methyl-2-butanol = (CH3)2C(OH)CH2CH3. Option (D) CH3CH2CH2MgBr + CH3CHO would give CH3CH(OH)CH2CH2CH3 = 2-pentanol (wrong product).
Q53(B)DMSO (polar aprotic) + 0°C + strong nucleophile OH: conditions favour SN2. 2-Bromobutane is secondary → SN2 gives 2-butanol. Higher temperature or alcoholic KOH would shift to E2.
Q54(B)Ethanol: reacts with Na → H2 (active O–H); oxidised by KMnO4 (alcohol → acid, decolourises); positive iodoform because CH3CH(OH)H has the CH3CHOH unit (secondary methyl alcohol = CH3CH2OH; iodoform: oxidised to CH3CHO then CHI3). All three tests consistent.
Q55(B)First mol RMgX opens epoxide → alkoxide R–CH2CH2–OMgX (this is a new metalated species that can act as another Grignard equivalent if needed, or simply as an alkoxide for other reactions). Key: only 1 equivalent of RMgX reacts with 1 mol epoxide in practice.
Q56(B)1-Butanol direct dehydration (H2SO4) gives Zaitsev product but-2-ene (not but-1-ene). To get but-1-ene from 1-butanol: tosylate formation then E2 with bulky base; but since C-1 is primary with only one β-carbon (C2), E2 gives exclusively but-1-ene regardless. Answer (B) is correct rationale.
Q57(B)Iodoform test positive for: (i) CH3CO– (methyl ketones), (ii) CH3CHO (acetaldehyde), (iii) CH3CH(OH)R (secondary alcohol where one R=H or other, oxidised in situ to methyl ketone/acetaldehyde). The key structural feature: CH3C(=O)– or CH3CH(OH)– unit.
Q58(A)Lucas test alone: 2-methylbutan-2-ol (tertiary) → immediate turbidity; pentan-2-ol (secondary) → turbid in 5 min with warming; pentan-1-ol (primary) → no turbidity at RT. One test distinguishes all three.
Q59(A)PhMgBr attacks cyclohexanone C=O (1,2-addition, hard nucleophile → hard site). Product: phenyl adds to the carbonyl C → 1-phenylcyclohexan-1-ol (tertiary alcohol). Grignard addition to ketones → tertiary alcohol.
Q60(A)Step 1: 1-methylcyclohex-1-ene + mCPBA → 1,2-epoxy-1-methylcyclohexane (syn epoxide). Step 2: LiAlH4 opens at less hindered C2 (SN2, anti) → trans-2-methylcyclohexanol (secondary alcohol). Step 3: PCC oxidises secondary OH → 2-methylcyclohexan-1-one (but the methyl is at C2 relative to OH; the ketone is at the former OH position → product is 2-methylcyclohexan-1-one).